1.

If I=∫31(tan−1(x2−5x+6x3−6x2+12x−7)+tan−1(1x2−4x+4)) then the value of [I] is (where [.] represents the greatest integer function)

Answer» If I=31(tan1(x25x+6x36x2+12x7)+tan1(1x24x+4)) then the value of [I] is
(where [.] represents the greatest integer function)


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