1.

If I have 1 L ammonia at room pressure and temperature (100 kPa, 20°C) how much mass is that?  

Answer»

Psat  = 857.5 kPa at 20°C so superheated vapor.

v = 1.4153 m3/kg under subheading 100 kPa

m = V/v = 0.001 m3/1.41153 m3/kg = 0.000 706 kg = 0.706 g   



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