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If I have 1 L ammonia at room pressure and temperature (100 kPa, 20°C) how much mass is that? |
Answer» Psat = 857.5 kPa at 20°C so superheated vapor. v = 1.4153 m3/kg under subheading 100 kPa m = V/v = 0.001 m3/1.41153 m3/kg = 0.000 706 kg = 0.706 g |
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