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If I is moment of inertia, of a disc about an axis passing through its centre then find change in moment of inertia due to sma,ll change in its temperature Delta(alpha is coefficient of linear expansion ). |
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Answer» SOLUTION :LET I ` = (MR^(2))/(2) " then " DELTA I = (M)/(2) 2R Delta R ` `(Delta I)/(I) = (MR Delta R )/(MR^(2)//2) = 2 (Delta R)/(R)` But `(Delta R)/(R) = alpha Delta trArr (Delta I )/(I) = 2 alpha Delta T and Delta I = 2I alpha Delta t.` |
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