1.

If I is moment of inertia, of a disc about an axis passing through its centre then find change in moment of inertia due to sma,ll change in its temperature Delta(alpha is coefficient of linear expansion ).

Answer»

SOLUTION :LET I ` = (MR^(2))/(2) " then " DELTA I = (M)/(2) 2R Delta R `
`(Delta I)/(I) = (MR Delta R )/(MR^(2)//2) = 2 (Delta R)/(R)`
But `(Delta R)/(R) = alpha Delta trArr (Delta I )/(I) = 2 alpha Delta T and Delta I = 2I alpha Delta t.`


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