1.

If I_(n) = int ("cosnx")/("cosx")dx then I_(n) =

Answer»

`- (2)/((N- 1)) " cos (n - 1) X" + I_(n - 2) `
`(2)/((n- 1)) " cos (n - 1) x" + I_(n - 2) `
` (2)/((n- 1)) " sin (n - 1) x" - I_(n - 2) `
`- (2)/((n- 1)) " sin (n - 1) x" + I_(n - 2) `

ANSWER :C


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