1.

If I_n = int_(pi//2)^(oo) e^(-x) x dx], then(I_(2018) )/(I_(2016)) =

Answer»

`(2018 XX 2019)/((2017)^2 + 1)`
`(2018 xx 2017)/((2018)^2 + 1)`
`( (2018)(2016) )/(2017)^2+ 1) `
`((2018)(2017) )/((2019)^2+ 1)`

ANSWER :B


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