1.

If I_(n)= int x^(n) e^(ax) then I_(n) - (x^(n) e^(ax))/(a ) =

Answer»

`(N)/(a) I_(n- 2)`
`(n)/(a) I_(n-2)`
`(n)/(a) I_(n- 1)`
`- (n)/(a) I_(n-1)`

ANSWER :D


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