1.

If I1=2π∫0ln(1−tan2x8)dx,I2=2π∫0ln(1+tan2x8)dx, then the value of (I1−I2) is

Answer»

If I1=2π0ln(1tan2x8)dx,I2=2π0ln(1+tan2x8)dx, then the value of (I1I2) is



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