1.

If in a 2 × 2 contingency table the frequencis of first order (A) = 130 and (B) = 120 then find the total frequency. 

Answer»

In a 2 × 2 contingeven table N – is frequency of zero order, is 

obtained as N = (A) + (B) 

∴ N = 130 + 120 = 250.



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