Saved Bookmarks
| 1. |
If in a 2 × 2 contingency table the frequencis of first order (A) = 130 and (B) = 120 then find the total frequency. |
|
Answer» In a 2 × 2 contingeven table N – is frequency of zero order, is obtained as N = (A) + (B) ∴ N = 130 + 120 = 250. |
|