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If in a class of 4 boys and 3 girls, find the probability of selection 2 students are (i) boys and (ii) girls. |
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Answer» n = 2 students can be selects from 4 boys and 3 girls = 7C, ways = 21 ways. Let P(A) = P(Boys selected) P(B) = P (girls selected) (i) p (A) = m/n = (412/712) = 6/21 (ii) p(B) = (312/712) = 3/21. |
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