1.

If in a class of 4 boys and 3 girls, find the probability of selection 2 students are (i) boys and (ii) girls.

Answer»

n = 2 students can be selects from 4 boys and 3 girls 

= 7C, ways = 21 ways.

Let P(A) = P(Boys selected)

P(B) = P (girls selected)

(i) p (A) = m/n = (412/712) 

= 6/21

(ii) p(B) = (312/712) 

= 3/21.



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