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If in a Delta ABC, O and O' are the incentre and orthocentre respectively, then (O' A+O'B +O'C) is equal to |
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Answer» SOLUTION :Here, `O'A =O'O+OA,` `O'B=O'O+OB and O'C =O'O +OC` `therefore O'A+O'B+O'C=3O'O+(OA+OB+OC)""…(i)` `because OA+OB+OC=O O' =-O'O` `therefore O'A+O'B+O'C =3O'O-O'O` [from EQ.(i)] `implies O'A+O'B+O'C=2O'O` |
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