1.

If in a Delta ABC, O and O' are the incentre and orthocentre respectively, then (O' A+O'B +O'C) is equal to

Answer»

`2O' O`
`O' O`
`OO'`
`2 OO'`

SOLUTION :Here, `O'A =O'O+OA,`
`O'B=O'O+OB and O'C =O'O +OC`

`therefore O'A+O'B+O'C=3O'O+(OA+OB+OC)""…(i)`
`because OA+OB+OC=O O' =-O'O`
`therefore O'A+O'B+O'C =3O'O-O'O` [from EQ.(i)]
`implies O'A+O'B+O'C=2O'O`


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