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If in a meter bridge experiment, the balancing length l was 25 cm for the situation shown in the figure. If the length and diameter of the of wire of resistance R is made half, then find the new balancing length in centimetre is |
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Answer» X/R = 75/25 = 3 R = ρl/A = 4ρl/πd2 R' = (4ρ(l/2))/π(d/2)2 = 2R then X/R' = ((100 - l)/l) (100 - l)/l = X/2R = 3/2 l = 40.00cm |
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