1.

If in a photoelectric experiment, the stopping potential is 1.5 volts, what is the maximum kinetic energy of a photoelectron ? [e = 1.6 × 10-19C]

Answer»

\(\cfrac12\)mv2max = Vse = ( 1.5)(1.6 × 10-19)

= 2.4 × 10-19 J is the required kinetic energy



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