InterviewSolution
Saved Bookmarks
| 1. |
If in a photoelectric experiment, the stopping potential is 1.5 volts, what is the maximum kinetic energy of a photoelectron ? [e = 1.6 × 10-19C] |
|
Answer» \(\cfrac12\)mv2max = Vse = ( 1.5)(1.6 × 10-19) = 2.4 × 10-19 J is the required kinetic energy |
|