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If in a triangle `ABC, 3 sin A = 6 sin B=2sqrt3sin C`, then the angle A isA. `0^(@)`B. `30^@`C. `60^(@)`D. `90^(@)` |
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Answer» Correct Answer - D `because 3 sin A=6 B=2sqrt(3).sinC` Dividing throughout by 6, `rArr (sinA)/(2)=(sinB)/(1)=(sinc)/(sqrt(3))` `rArr (a)/(2)=(b)/(1)=(c)/(sqrt(3))=K` `therefore b^2+c^2=a^2` `therefore angle A =90^@` |
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