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If in a Vernier callipers 10 VSD coincides with 8 MSD, then the least count of Vernier calliper is [given 1 MSD = 1mm]A. `1xx10^(-4)m`B. `2xx10^(-4)m`C. `1xx10^(-3)m`D. `8xx10^(-4)m` |
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Answer» Correct Answer - B |
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