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If in an alternating current circuit, capacitance C is connected to a supply of 200V,50Hz. Current in the circuit is 1.89 A. Find the capacitance C.(a) 30 µF(b) 20 µF(c) 10 µF(d) 15 µF

Answer» The correct choice is (a) 30 µF

To explain I would say: XC= V/I = 200/1.89 = 106.1 Ω.                                                                                                                                                            XC=1/(2πfC)   Substituting the values we get C = 30 µF.


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