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If in an alternating current circuit, capacitance C is connected to a supply of 200V,50Hz. Current in the circuit is 1.89 A. Find the capacitance C.(a) 30 µF(b) 20 µF(c) 10 µF(d) 15 µF |
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Answer» The correct choice is (a) 30 µF To explain I would say: XC= V/I = 200/1.89 = 106.1 Ω. XC=1/(2πfC) Substituting the values we get C = 30 µF. |
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