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If in circular coil of radius `R`, current `I` is flowing and in another coil `B` of radius `2R` a current `2I` is flowing , then the raatio of the magnetic fields `B_(A) and B_(B)`, produced by them will beA. `1`B. `2`C. `(1)/(2)`D. `4)` |
Answer» Correct Answer - A KEY CONCEPT : we know that the magnetic field produced by a current carrying circular coil of radius `r` at its centre is `B = (mu_(0))/(4pi) (I)/( r) xx2 pi` Here `B_(A) = (mu_(0))/(4pi) (I)/( r) xx2 pi and B_(B) = (mu_(0))/(4pi) (2I)/( 2r) xx2 pi` rArr `(B_(A))/(B_(B)) = 1` |
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