If in ΔABC with usual notations a = 18, b = 24, c = 30 then sin \(\fr

1.	If in ΔABC with usual notations a = 18, b = 24, c = 30 then sin \(\frac{A}{2}\) is equal to(A) \(\frac{1}{\sqrt 5}\)(B) \(\frac{1}{\sqrt 10}\)(C) \(\frac{1}{\sqrt {15}}\)(D) \(\frac{1}{2\sqrt 5}\)
Answer» Answer is: (B) \(\frac{1}{\sqrt{10}}\) s = \(\frac{a+b+c}{2}=\frac{18+24+30}{2}=36\) sin \(\frac{A}{2} = \sqrt \frac{(s-b)(s-c)}{bc}=\sqrt\frac{(36-24)(36-30)}{24\times30}=\sqrt\frac{12\times6}{24\times30}=\frac{1}{\sqrt{10}}\)

If in ΔABC with usual notations a = 18, b = 24, c = 30 then sin \(\frac{A}{2}\) is equal to(A) \(\frac{1}{\sqrt 5}\)(B) \(\frac{1}{\sqrt 10}\)(C) \(\frac{1}{\sqrt {15}}\)(D) \(\frac{1}{2\sqrt 5}\)

Answer»

Answer is: (B) \(\frac{1}{\sqrt{10}}\)

s = \(\frac{a+b+c}{2}=\frac{18+24+30}{2}=36\)

sin \(\frac{A}{2} = \sqrt \frac{(s-b)(s-c)}{bc}=\sqrt\frac{(36-24)(36-30)}{24\times30}=\sqrt\frac{12\times6}{24\times30}=\frac{1}{\sqrt{10}}\)

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If in ΔABC with usual notations a = 18, b = 24, c = 30 then sin \(\frac{A}{2}\) is equal to(A) \(\frac{1}{\sqrt 5}\)(B) \(\frac{1}{\sqrt 10}\)(C) \(\frac{1}{\sqrt {15}}\)(D) \(\frac{1}{2\sqrt 5}\)

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