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If in the expansion f `(1+x)^m(1-x)^n, the coefficient of x and `x^2` are 3 and -6 respectively then (A) m=9 (B) n=12 (C) m=12 (D) n=9A. 6B. 9C. 12D. 24 |
Answer» `(1+x)^m(1-x)^n=[1+mx+(m(m-1))/(2)x^2+......]` `[1-nx+(n(n-1))/(2)x^2+.......]` `=1+(m-n)x+[(m(m-1))/(2)+(n(n-1))/(2)-mn]x^2+......` term containg power of `x ge 3`. Now `m-n=3 .....(i)` and `(1)/(2)m(m-1)+(1)/(2)n(n-1)-mn=-6`. `rArr m(m-1)+nn(n-1)-2mn=-12`. `rArr m^2-m+n^2-n-2mn=-12` `rArr (m-n)^2-(m+n)=-12` `rArr m=n=9+12=21....(ii)`. On solving Eqs.(i) and (ii), we get `m=12`. |
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