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If in the shown figure `AC=hati+2hatj+4hatk` and `BD=hati-3hatj+hatk` then BC is A. `(3)/(2)hati-(1)/(2)+5hatk`B. `(3)/(2)hati-2hatj+3hatk`C. `3hati-hatj+5hatk`D. `hati-(1)/(2)hatj+(5)/(2)k` |
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Answer» `AB+BC=AC=hati+2hatj+4hatk` `BC-AB=BD=hati-3hatj+hatk` `2BC=2hati-hatj+5hatk` `rArrBC=hati-(hatj)/(2)+(5)/(2)hatj` |
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