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If in triangle ABC, `(a=(1+sqrt(3))c m ,b=2c m ,a n d/_C=60^0`, then find the other two angles and the third side. |
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Answer» From `cos C = (a^(2) + b^(2) - c^(2))/(2ab)`, we have `(1)/(2) = ((1 + sqrt3)^(2) + 4 -c^(2))/(2(1 + sqrt3) 2)` or `2 + 2sqrt3 = 1+ 3 + 2sqrt3 + 4 - c^(2)` or `c^(2) = 6 " or " c = sqrt6 cm` Also, `(sin A)/(a) = (sin B)/(b) = (sin C)/(c)` or `(sin A)/(1 + sqrt3) = (sin B)/(2) = (sqrt3//2)/(sqrt6)` `rArr sin B = (1)/(sqrt2) " or " B = 45^(@)` and `A = 180^(@) - (60^(@) + 45^(@)) = 75^(@)` |
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