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In `DeltaABC, R, r, r_(1), r_(2), r_(3)` denote the circumradius, inradius, the exradii opposite to the vertices A,B, C respectively. Given that `r_(1) :r_(2): r_(3) = 1: 2 : 3` The sides of the triangle are in the ratioA. `1 : 2 : 3`B. `3 : 5 : 7`C. `1 : 5 : 9`D. `5 : 8 : 9` |
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Answer» Correct Answer - D `(Delta)/(s-a) : (Delta)/(s-b): (Delta)/(s-c) = 1: 2:3` Let `(Delta)/((s-a)/(1)) = (Delta)/((s-b)/(2)) = (Delta)/((s-c)/(3)) = (Delta)/(6k)` `rArr (1)/(s-a) = (1)/(6k), (1)/(s-b)= (1)/(3k), (1)/(s-c) = (1)/(2k)` `rArr s-a = 6k, s-b = 3k, s-c = 2k` `rArr s= 11k` `:. a = 5k, b= 8k, c = 9k` Hence, ratio of sides is `5: 8: 9` |
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