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If In=∫xn√a2−x2dx and (n+k)⋅In=−xn−1(a2−x2)p+(n−1)a2⋅In−2, then 3k−2p=(where m,n∈N;m,n≥2) |
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Answer» If In=∫xn√a2−x2dx and (n+k)⋅In=−xn−1(a2−x2)p+(n−1)a2⋅In−2, then 3k−2p= (where m,n∈N;m,n≥2) |
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