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If `int_(-20)^(-10)((x^(2)-x)/(x^(3)-3x+1))^(2)+dx+int_(1/21)^(1/11)((x^(2)-x)/(x^(3)-3x+1))^(2)dx + int_(21/20)^(11/10)((x^(2)-x)/(x^(3)-3x+1))^(2)dx=l` then `l+420/7939` is equal toA. `110/939`B. `110/969`C. `110/739`D. `120/759` |
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Answer» Correct Answer - B Put `x=1/(1-t)` in `l_(2)` and `x=1-1/t` in `l_(3)` We get `l=int_(-20)^(-10) ((x^(2)-x)/(x^(3)-3x+1))(1+1/(x^(2))+1/(1-x)^(2))dx` Let `u=(x^(3)-3x+1)/(x(x-1))` then `l= int(du)/(u^(2))` |
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