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`"If " int(cos 4x+1)/(cotx-tanx)dx=Acos4x+B, " then "`A. `A=-1//2`B. `A=-1//8`C. `A=-1//4`D. non of these |
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Answer» Correct Answer - B `int(cos4x+1)/(cotx-tanx)dx=int(2cos^(2)2x)/(cos^(2)x-sin^(2)x)sinx cosx dx` `=int cos2x sin2x dx` `=(1)/(4)int sin4xdx=-(1)/(8)cos4x+C` |
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