If (k – 3), (2k + 1) and (4k + 3) are three consecutive terms of an – InterviewSolution

InterviewSolution

1.

If (k – 3), (2k + 1) and (4k + 3) are three consecutive terms of an A.P., find the value of k.

Answer»

Here, ft – 3, 2k + 1 and 4k + 3 are three consecutive terms of an A.P.

∴ 2k + 1 – (k – 3) = 4k + 3 – (2k + 1)

⇒ 2k + 1 – k + 3 = 4k + 3 – 2k – 1

⇒ k + 4 = 2k + 2

⇒ 2k – k =4 – 2

⇒ k = 2

Hence, the value of ft is 2.

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