If K_(b) and K_(f) for a reversible reactions are 0.8xx10^(-5) and 1.6xx10^(-4) respectively, the value of the equilibrium constant is,

If K_(b) and K_(f) for a reversible reactions are 0.8xx10^(-5) and 1.6

1.	If K_(b) and K_(f) for a reversible reactions are 0.8xx10^(-5) and 1.6xx10^(-4) respectively, the value of the equilibrium constant is,
Answer» 20 `0.2xx10^(-1)` `0.05` none of these SOLUTION :Equilibrium constant, `K_(C)` is equal to `K_(B)//k_(f)`