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| 1. |
If k. E of a body increase by 100 % how much % of momentum will increased |
| Answer» Kinetic energy = p^2/2m If the momentum increases by 100% , then the p increases to 2p.Substitute p =1K before increase in momentum = p^2/2m = 1/2m - (1)K\' after increase in momentum by 100% = 2p^2/2m= 4/2m - (2)Let p = 1\xa0Divide (2) by (1) and substitute p=1K\'/K = (4/2m) / (1/2m) = 4 ( 2m gets divided by 2m to give 1) K\'= 4K ( cross-multiplication)Percentage increase = (K\'-K / K) * 100 = (4K-K/K) *100 = (3K /K)\xa0*100 = 3*100 = 300%When momentum of a body increases by 100% then its kinetic energy will increase by 300%. | |