1.

If K_(sp) of CaSO_4. 5H_2O is 9xx10^(-6) . Find the volume of 1 gm CaSO_4. (M.M = 136u)

Answer»

2.45 litre
5.1 litre
4.52 litre
3.2 litre

Solution :`CaSO_(4(s)) HARR Ca_((aq))^(2+) + SO_(4(aq))^(2-)`
`K_(SP)=S^2=9xx10^(-6)`
`S=3xx10^(-3)` mole/litre
mg/litre = M.M x S
`=136xx3xx10^(-3)`
`=408xx10^(-3)` GM/litre
In 1 litre `408xx10^(-3)`gm `CaSO_4`
`therefore` 1 gm `CaSO_4 = 1/(408xx10^(-3))`=2.45 litre


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