If K1 ≤ P ≤ K2 where P is probability of any event of random exp

1.	If K1 ≤ P ≤ K2 where P is probability of any event of random experiment, then the possible maximum K2 + possible least value of K1 is …………A) 1 B) 0 C) 2 D) cannot be determined
Answer» Correct option is: A) 1 \(\because\) P is probability of any event of random experiment. \(\therefore\) 0 \(\leq\) P \(\leq\) 1 But given that \(K_1\) \(\leq\) P \(\leq\) \(K_2\) \(\therefore\) 0 \(\leq\) \(K_1\) \(\leq\) P \(\leq\) \(K_2\) \(\leq\) 1 \(\therefore\) Possible maximum value of \(K_2\) is 1 and possible least value of \(K_1\) is 0. \(\therefore\) Possible maximum \(K_2\) + possible least value of \(K_1\) = 1 + 0 = 1 Correct option is: A) 1

If K1 ≤ P ≤ K2 where P is probability of any event of random experiment, then the possible maximum K2 + possible least value of K1 is …………A) 1 B) 0 C) 2 D) cannot be determined

Answer»

Correct option is: A) 1

\(\because\) P is probability of any event of random experiment.

\(\therefore\) 0 \(\leq\) P \(\leq\) 1

But given that \(K_1\) \(\leq\) P \(\leq\) \(K_2\)

\(\therefore\) 0 \(\leq\) \(K_1\) \(\leq\) P \(\leq\) \(K_2\) \(\leq\) 1

\(\therefore\) Possible maximum value of \(K_2\) is 1

and possible least value of \(K_1\) is 0.

\(\therefore\) Possible maximum \(K_2\) + possible least value of \(K_1\)

= 1 + 0 = 1

Correct option is: A) 1

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If K1 ≤ P ≤ K2 where P is probability of any event of random experiment, then the possible maximum K2 + possible least value of K1 is …………A) 1 B) 0 C) 2 D) cannot be determined

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