If Ka of weak acid is found to be 1.78xx10^(-5) What is the PK_(a) val

1.	If Ka of weak acid is found to be 1.78xx10^(-5) What is the PK_(a) value?
Answer» SOLUTION :`Ka=1.78xx10^(-5)` `PK_(a)=-logKa=-log(1.78xx10^(-5))=-log1.78+5log10=-0.2504+5=4.7496`

Discussion