If kinetic energy of an electron is increased by nine times, the wavelength associated with it would become ...........

If kinetic energy of an electron is increased by nine times, the wavel

1.	If kinetic energy of an electron is increased by nine times, the wavelength associated with it would become ...........
Answer» `1/3` times `1/9` times 9 times 3 times Solution :kinetic energy =`1/2 mV^(2)` … and `lambda=(h)/(mV)` `THEREFORE V=(h)/(lambdav)` and `v^(2) =(h^(2))/(lambda^(2)m^(2))` `therefore KE ALPHA (1)/(lambda^(2))` If KE is INCREASED by nine times `therefore 9=(lambda_(1)^(2))/(lambda_(2)^(2))` `therefore 3=(lambda_(1))/(lambda_(2))` and `(lambda_(2))/(lambda_(1))=1/3`