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If `L = (20 +- 0.01) m` and `B = (10 +- 0.02)m` then `L//B` isA. `(2 +- 0.03)m`B. `(2 +- 0.15)m`C. `(2 +- 0.01)m`D. `(2 +- 0.05)m` |
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Answer» Correct Answer - D `(Delta x)/(x) xx (Delta L)/(L) + (Delta B)/(B) implies Deltax = x [(Delta L)/(L) + (Delta B)/(B)]` `= (20)/(10) [(0.01)/(20) + (0.02)/(10)]` `x +- Delta x = (2 +- 0.005)m` |
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