If L = 20.04 m pm0.01 m , B= 2.52 m pm0.02 m . What are the values of (L xx B) and (L+B) ?

If L = 20.04 m pm0.01 m , B= 2.52 m pm0.02 m . What are the values of

1.	If L = 20.04 m pm0.01 m , B= 2.52 m pm0.02 m . What are the values of (L xx B) and (L+B) ?
Answer» Solution :Given errors are absolute errors, while the rule says that percentage errors are to be added . Hence, the first step will be to convert the given absolut errors into percentage errors. `L=20.04m+-(0.01)/(20.04)XX100%=20.04m+-0.05%` `B=2.52m+-(0.02)/(2.52)xx100%=2.52m+-0.79%` `LxxB=(20.04xx2.52)m^(2)+-(0.05+0.79)%=50.50m^(2)+-0.84%` This is the result . However, since the data GIBEN the QUESTION was in terms of absolute errors, so we should give our result also in absolute errors. `LxxB=50.50m^(2)+-(0.84)/(100)xx50.50m^(2)=50.50m^(2)+-0.42m^(2)`