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If L = 20.04 mpm 0.01 m B = 2.52 m pm 0.02m What are the values of (L//B)? |
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Answer» Solution :Given errors are absolute errors, while the RULE SAYS that percentage errors are to be added. Hence, the first step will be to convert the given absolute errors intopercentage errors. `L= 20.04 m pm (0.01)/( 20.04) XX 100% = 20.04 pm 0.05 %` `B = 2.52 m pm (0.02)/( 2.52)xx 100% = 2.52 m pm 0.79%` `L xx B = (20.04 xx 2.52) m^(2) pm (0.05 + 0.79 )%` `= 50.50 m^(2) pm 0.84 %` This is the result. However, since the data given in the question was in TERMS of absolute errors, so we should GIVE our result also in absolute errors. `L xx B = 50.50m^(2) pm (0.84)/( 100) xx 50.50 m^(2)` `= 50.50 m^(2) pm 0.42 m^(2)` |
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