If L=(4tan1∘)(4tan2∘)(4tan3∘)…(4tan10∘),M=(tan2∘)(tan4∘) – InterviewSolution

1.	If L=(4tan1∘)(4tan2∘)(4tan3∘)…(4tan10∘),M=(tan2∘)(tan4∘)(tan6∘)…(tan20∘), and N=(1+tan1∘)(1−tan1∘)(1+tan2∘)(1−tan2∘)…(1+tan10∘)(1−tan10∘), then the value of L128MN is
Answer» If $L = (4 tan 1^{\circ}) (4 tan 2^{\circ}) (4 tan 3^{\circ}) \dots (4 tan 10^{\circ}),$ $M = (tan 2^{\circ}) (tan 4^{\circ}) (tan 6^{\circ}) \dots (tan 20^{\circ}),$ and $N = (1 + tan 1^{\circ}) (1 - tan 1^{\circ}) (1 + tan 2^{\circ}) (1 - tan 2^{\circ}) \dots (1 + tan 10^{\circ}) (1 - tan 10^{\circ})$ , then the value of $\frac{L}{128 M N}$ is

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