InterviewSolution
Saved Bookmarks
| 1. |
If L denotes the inductance of an inductor through which a current i is flowing, the dimensions of Li2 are (A) [L2 M1 T-2] (B) Not expressible in LMT (C) [L1 M1 T-2] (D) [L2 M2 T-2] |
|
Answer» Answer is (A) [L2 M1 T-2] \(\frac{1}{2}\) Li2 = energy stored in an inductor = [M1 L2 T-2] |
|