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If `l=intsec^2xcos e c^4x dx=Acot^3x+Btanx+Ccotx+D ,`then`A=-1/3`(b) `B=2``C=-2`(d) none of theseA. `A=-(1)/(3)`B. `B=2`C. `C=-2`D. none of these |
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Answer» Correct Answer - A::C `I=int sec^(2)x "cosec"^(4)xdx` `=int((sin^(2)x+cos^(2)x)^(2))/(cos^(2)xsin^(4)x)dx` `=int(sin^(4)x+cos^(4)x+2sin^(2)x cos^(2)x)/(cos^(2)xsin^(4)x)dx` `=int(sec^(2)x+2"cosec"^(2)x+(cos^(2)x)/(sin^(4)x))dx ` `=tanx-2cotx+int cot^(2)x"cosec"^(2)x dx` `=tanx-2cotx-(cot^(3)x)/(3)+D` |
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