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If length and breath of a plate are `(40 +- 0.2)cm` and `(30 +- 0.1 ) cm`, the absolute error in the meaurement of area isA. `10 cm^(2)`B. `8 cm^(2)`C. `9cm^(2)`D. `7cm^(2)` |
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Answer» Correct Answer - A `A = lb implies (Delta A)/(A) = (Delta l)/(l) + (Delta b)/(b) implies Delta A = A [(Delta l)/(l) + (Delta b)/(b)]` `Delta A = b Delta l + l Delta b = 10cm^(2)` |
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