1.

If light of wavelength 412.5 nm is incident on each of the metals given below, which one will show photoelectric emission and why? .

Answer» Metal will show photoelectric emission only when energy of incident photons is greater than work function of that metal.
`E = 1240// 421.5 mm`
` E = 3eV`
It is greater than Na and K , so only those two will exit photoelectrons.


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