

InterviewSolution
Saved Bookmarks
1. |
If light of wavelength 412.5 nm is incident on each of the metals given below, which one will show photoelectric emission and why? . |
Answer» Metal will show photoelectric emission only when energy of incident photons is greater than work function of that metal. `E = 1240// 421.5 mm` ` E = 3eV` It is greater than Na and K , so only those two will exit photoelectrons. |
|