1.

If lim_(n to infty)((n!)1/n)/n=L where n in N, then the absolute value of log_(e)(L) is

Answer»

1
`1/2`
`1/3`
2

Solution :LN L`=lim_(n to infty) ln ((n!)/(n^(n))^(1/n))`
`=lim_(n to infty) sum_(r=1)^(n) 1/n ln(r/n)`
`=int_(0)^(1) (ln X)dx=-1`


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