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If lim_(xrarroo) xlog_(e)(|(alpha//x,1,gamma),(0,1//x,beta),(1,0,1//x)|)=-5. where alpha, beta, gamma are finite real numbers, then |
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Answer» `alpha=2, BETA=1, gamma in R` `=underset(xrarroo)(lim)x.log_(e)((alpha)/(x^(3))+beta-(gamma)/(x))` For LIMIT to EXIST, `beta=1` `therefore""L=underset(xrarroo)(lim)x.log_(e)(2+(alpha)/(x^(3))-(gamma)/(x))` `=underset(xrarroo)(lim)x((alpha)/(x^(3))-(gamma)/(x))` `=underset(xrarroo)(lim)((alpha)/(x^(2))-gamma)=-gamma=-5 and alpha in R` |
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