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If limn→∞(1√4n2−1+1√4n2−22+⋯+1√3n)=πa, then the unit digit of (a2020+2019) is |
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Answer» If limn→∞(1√4n2−1+1√4n2−22+⋯+1√3n)=πa, then the unit digit of (a2020+2019) is |
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