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If limn→∞n∑a=2sin−1[√(a2+2a)−√(a−1)(a+1)a(a+1)]=kπ120, then the value of k is

Answer» If limn→∞n∑a=2sin−1[√(a2+2a)−√(a−1)(a+1)a(a+1)]=kπ120, then the value of k is


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