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If limx→0(ax+bx+cx+dx4)1/x=8, then the minimum value of the determinant ∣∣∣a+ibc+id−c+ida−ib∣∣∣ is

Answer» If limx0(ax+bx+cx+dx4)1/x=8, then the minimum value of the determinant a+ibc+idc+idaib is


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