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If limx→∞(√x2−x+1−ax−b)=0, then for k≥2, limn→∞sec2n(k! πb) is equal to |
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Answer» If limx→∞(√x2−x+1−ax−b)=0, then for k≥2, limn→∞sec2n(k! πb) is equal to |
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