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                                    If limx→∞(√x2−x+1−ax−b)=0, then for k≥2, limn→∞sec2n(k! πb) is equal to | 
                            
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Answer»  If limx→∞(√x2−x+1−ax−b)=0, then for k≥2, limn→∞sec2n(k! πb) is equal to  | 
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