1.

If linear momentum of a body is increased by 0.5% its kinetic energy increases b y ..

Answer»

0.1
0.01
0.02
0

Solution :`1 %`
`k= (p^(2))/( 2M )` WHERE2 m ISEQUAL
`k= P^(2)`
`(Delta k )/( k ) = (2Delta p )/( p )`
`(Delta k )/( k ) xx 100= 2xx (Delta p ) /( p ) xx 100`
`=2 xx 0.5 %`
`=1.0 %`


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