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| 1. |
if log 3 = 0.4711, find the number of digits in 3^(43) |
| Answer» Solution :Let `x=3^(43)thereforelogx=LOG3^(43)=43log3=43xx0.4771=20.5153` Since the characteristic of `log3^(43)` is 20, then NUMBER of digits in `3^(43)` is `(20+1)=21.` | |