1.

if log 3 = 0.4711, find the number of digits in 3^(43)

Answer»

Solution :Let `x=3^(43)thereforelogx=LOG3^(43)=43log3=43xx0.4771=20.5153` Since the characteristic of `log3^(43)` is 20, then NUMBER of digits in `3^(43)` is `(20+1)=21.`


Discussion

No Comment Found