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If `log_(4)(x - 1) = log_(2)(x - 3)` , then `x` may beA. `x = 5`B. `x = 9`C. `x = 2`D. `x = 4` |
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Answer» Correct Answer - A `x - 1 = (x - 3)^(2) rArr x^(2) - 7 x + 10 = 0` `x = 5, 2` only `x = 5` |
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