1.

If |log2x+1|+|1−log22x|=|log2x+log22x|, then the true set of values of x is {λ}∪[μ,∞). Then

Answer»

If |log2x+1|+|1log22x|=|log2x+log22x|, then the true set of values of x is {λ}[μ,). Then



Discussion

No Comment Found