InterviewSolution
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If |log2x+1|+|1−log22x|=|log2x+log22x|, then the true set of values of x is {λ}∪[μ,∞). Then |
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Answer» If |log2x+1|+|1−log22x|=|log2x+log22x|, then the true set of values of x is {λ}∪[μ,∞). Then |
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